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Find the roots of the quadratic equation 25x2-10ax+a2-16b2=0 by using factorization. |
Answer» 25x²-10x+a²-16b²D=b²-4ac D=(-10a)²-4(25)(a²-16b²) D=100a²-100a²+1600b² D=1600b² x= {-(-10a)+√1600b²}/2(25) , {-(-10a)-√1600b²}/2(25) x= (10a+40b)/2 , (10a-40b)/2 x= 5a+20b , 5a-20b HOPE THE ANSWER HELPED YOU☺️☺️ |
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