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Find the roots of quadratic equations 4x2 - 2(a2 + b2)x + a2b2 = 0 |
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Answer» Given 4x2 - 2(a2 + b2)x + a2b2 = 0 ⇒ 4x2 - 2a2x - 2b2x + a2b2 = 0 ⇒ 2x(2x - a2) - b2(2x - a2) = 0 ⇒ (2x - b2) (2x - a2) = 0 ⇒ 2x - b2 = 0 or 2x - a2 = 0 ⇒ x = b2/2 or x = a2/2 Hence, the roots of the equation are b2/2 and a2/2 |
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