1.

Find the roots of quadratic equations 12abx2 - (9a2 - 8b2)x - 6ab = 0

Answer»

Given

12abx2 - (9a2 - 8b2)x - 6ab = 0

⇒ 12abx2 - 9a2x + 8b2x - 6ab = 0

⇒ 3ax (4bx - 3a) + 2b (4bx - 3a) = 0

⇒ (3ax + 2b) (4bx - 3a) = 0

⇒ 3ax + 2b = 0 or 4bx - 3a = 0

⇒ x = -2b/3a or x = 3a/4b

Hence, the roots of the equation are -2b/3a and 3a/4b.



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