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Find the roots of 2π2 -5π+7=0 |
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Answer» ONG>Answer: PLEASE BRAINLIEST MY ANSWER x = {5 ± i√31} / 4 Step-by-step explanation: Q) find the roots of 2π2 -5π+7=0 ⇒ Given equation is 2π² - 5π + 7 = 0 put the π = x ∴ 2x² - 5x + 7 = 0 we know the formula for FINDING x from equation ax² + bx + c = 0 is x = [-b ± √(b²-4ac)] / 2a ∵ a=2, b= -5, c=7 x = {-(-5) ± √[(-5)²-4*2*7]} / 2*2 = {5 ± √[25-56]} / 4 = {5 ± √[-31]} / 4 = {5 ± √[31*(-1)]} / 4 x = {5 ± i√31} / 4 |
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