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Find the resistance of a bulb, on which 60W and 120 V is marked. |
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Answer» <P> SOLUTION :P = 60W, V = 120 VWe know P = VI `rArr(V_(2))/(R)(becauseI=(V)/(R))` `rArrR=(V_(2))/(R)=(120xxcancel(120))/(CANCEL(60))=240Omega.` |
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