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Find the remainder when x³+3x²+1 is divided by x—½ ,x ,x+π |
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Answer» Answer:X-½=0 Answer:x-½=0 x=½ Answer:x-½=0 x=½ p(x)=x³+3x²+1 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π π=22/7 Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π π=22/7p(x)=x³+3x²+1 p(22/7)=( 22/7)³+3.(22/7)²+1 = 31.04(approx) + 29.61 +1 = 61.65(approx)
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