1.

Find the ratio of energies of 2nd and 3rd orbit of He+ and Li2+ respectively.​

Answer»

Answer:

1:1

Explanation:

LISTEN E=-kz^2 ÷n^2

For finding ratio we just have to DEVIDE, the respective atomic and orbit number asked and use the above formula we GET :(z1÷z2) ^2 ÷(n1÷n2) ^2

(2÷3)^2 ×(3÷2) ^2

THEREFORE answer is 1:1

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