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Find the ratio of energies of 2nd and 3rd orbit of He+ and Li2+ respectively. |
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Answer» Answer: 1:1 Explanation: LISTEN E=-kz^2 ÷n^2 For finding ratio we just have to DEVIDE, the respective atomic and orbit number asked and use the above formula we GET :(z1÷z2) ^2 ÷(n1÷n2) ^2 (2÷3)^2 ×(3÷2) ^2 THEREFORE answer is 1:1 IF you like my answer then please brainliest it :) |
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