Find the ratio in which the point (-3, p) divides the line segment joi

1.	Find the ratio in which the point (-3, p) divides the line segment joining the points (5, - 4) and(-2, 3) Hence, find the value of p.
Answer» (x1,y1)=(-5,-4), (x2,y2) = (-2,3)(-3,p) is the point which divides joining the above points in the ratio k:1by using section formula [(k(-2)+15)/(k+1) , (k3+1(-4))/(k+1)] = (-3,p)equating x co ordinates(-2k+5)/(k+1) = -3-2k+5 = -3(k+1)-2k+5 = -3k-3-2k+3k=-3-5k= -8---(1) equating y co ordinates(3k-4)/(k+1) = psubstitute k = -8 [3*(-8) -4]/(-8+1) = p (-24-4)/-7 = p-28/-7 =p4=pp=4

Find the ratio in which the point (-3, p) divides the line segment joining the points (5, - 4) and(-2, 3) Hence, find the value of p.

Answer»

(x1,y1)=(-5,-4), (x2,y2) = (-2,3)(-3,p) is the point which divides joining the above points in the ratio k:1by using section formula

[(k*(-2)+1*5)/(k+1) , (k*3+1*(-4))/(k+1)] = (-3,p)equating x co ordinates(-2k+5)/(k+1) = -3-2k+5 = -3(k+1)-2k+5 = -3k-3-2k+3k=-3-5k= -8---(1)

equating y co ordinates(3k-4)/(k+1) = psubstitute k = -8 [3*(-8) -4]/(-8+1) = p

(-24-4)/-7 = p-28/-7 =p4=pp=4