1.

Find the ratio in which the point (2, 5) divides the line segment (8,2) and(-6,9)​

Answer»

The required ratio is 3:4.

Step-by-step explanation:

Since we have given that

(2,5)  divides the line segment (8,2) and (-6,9)

Let the ratio be k:1.

Using "SECTION formula", we get that

(\dfrac{8-6k}{k+1},\dfrac{9-2k}{k+1})=(2,5)\\\\\dfrac{8-6k}{k+1}=2\\\\8-6k=2(k+1)\\\\8-6k=2k+2\\\\8-2=2k+6k\\\\6=8k\\\\k=\dfrac{6}{8}=\dfrac{3}{4}

Hence, the required ratio is 3:4.

# learn more:

Find the coordinates of the POINT dividing internally the line segment JOINING a(3,7) and b(8,2) in the ratio 2:3.

brainly.in/question/8281975


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