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Find the rate of change of radius of a sphere when its radius is `4 cm` and when its volume is changing at the rate of `(4pi)/(625)m^(3)//sec`A. `1m//s`B. `2m//s`C. `pim//s`D. `3m//s` |
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Answer» Correct Answer - A `V=(4)/(3)piR^(3)` `(dV)/(dt)=4piR^(2)(dR)/(dt)` `rArr(4pi)/(625)=4pi xx(4)/(100)xx(4)/(100)xx(dR)/(dt)` `rArr(dR)/(dt)=1m//s` |
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