1.

Find the range of the following functionsf(x)=2.5x+6, domain {x∈R,-5≤x≤5} f(x)=x^2+16, domain {x∈R,0≤x≤10}

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ANSWER:

(I)F(X)=2.5x+6

2.5x+6=0

2.5x=-6

x=-6/2.5

x=60/25

x=12/5

x=2.4

(II)f(x)=+16

x²+16=0

=-16

x=-16

x=4

Hope it WORKS................................✌️✌️



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