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Find the range of the following functionsf(x)=2.5x+6, domain {x∈R,-5≤x≤5} f(x)=x^2+16, domain {x∈R,0≤x≤10} |
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Answer» 2.5x+6=0 2.5x=-6 x=-6/2.5 x=–60/25 x=12/5 x=–2.4 (II)f(x)=x²+16 x²+16=0 x²=-16 x=√-16 x=4 Hope it WORKS................................™✌️✌️ |
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