Find the range of`f(x)=tan^(-1)sqrt((x^2-2x+2))` – InterviewSolution

1.	Find the range of`f(x)=tan^(-1)sqrt((x^2-2x+2))`
Answer» Correct Answer - `[pi//4,pi//2)` `f(x)=tan^(-1)(sqrt((x-1)^(2)+1))` Now, `(x-1)^(2) +1 in [1,oo)` or `tan^(-1)(sqrt((x-1)^(2)+1))in [(pi)/(4),(pi)/(2))`

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