Find the range of `f(x)=sin^2x-sinx+1.` – InterviewSolution

1.	Find the range of `f(x)=sin^2x-sinx+1.`
Answer» `f(x)=sin^(2)x-sinx +1=(sinx - (1)/(2))^(2)+(3)/(4)` Now, ` -1 le sinx le 1 " or " -(3)/(2) le sinx-(1)/(2) le (1)/(2)` or ` o le (sinx -(1)/(2))^(2) le (9)/(4) " or " (3)/(4) le (sinx -(1)/(2))^(2) l+ (3)/(4) le 3` Hence, the range is `[(3)/(4),3]`.

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