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Find the range of `f(x)=1/(1-3sqrt(1-sin^2x))` |
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Answer» Correct Answer - `(-oo,1//2] cup [1,oo)` `f(x)=(1)/(1-3sqrt(1-sin^(2)x))=(1)/(1-3sqrt(cos^(2)x))` `=(1)/(1-3|cosx|)` Now, `-3|cosx| in [-3,0]` or `1-3|cosx| in[-2,1]` or `(1)/(1-3|cosx|) in (-oo,-1//2] cup [1,oo)` |
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