Find the radius of the circle in which a central angle of 60° interce

1.	Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).
Answer» $\dag{.}$ LET the radius of circle be "R" central ANGLE(¥) =60° = π/ 3 radiant arc LENGTH (l) = 37.4 we know from formula... central angle (¥) = arc length(l) ÷ radius =). π/3 = 37.4 / r =). r = 37.4 ×3 /π = 112.2 / π CM =). r = 112.2 ×7/ 22 = 35.7 cm ans

Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).

Answer»

$\dag{.}$

LET the radius of circle be "R"

central ANGLE(¥) =60° = π/ 3 radiant

arc LENGTH (l) = 37.4

we know from formula...

central angle (¥) = arc length(l) ÷ radius

=). π/3 = 37.4 / r

=). r = 37.4 ×3 /π = 112.2 / π CM

=). r = 112.2 ×7/ 22 = 35.7 cm ans

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Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).

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