Saved Bookmarks
| 1. |
Find the radius of the circle in the diagram below if BC is 20 ft and CE is 8 feet with work shown? |
|
Answer» Given : a circle of RADIUS r is SHOWN in above where BC = 20 ft and CE = 8 ft. To FIND : The radius of the circle. solution : here BC is a tangent to the circle which touches at B. if we join B to centre (let O) then, ∆BOC is a right angled triangle. from Pythagoras theorem, OC² = BO² + BC² ⇒(r + 8)² = r² + 20² ⇒r² + 16r + 64 = r² + 400 ⇒16r = 400 - 64 = 336 ⇒r = 21 Therefore the radius of the circle is 21 ft. also read similar questions : What is the area of a triangle that has a base of 3 FEET and a height of 6 feet? 18 ft 2 18 ft 9 ft 2 4.5 ft 2 If the area of a circle is 81pi SQUARE feet, find its circumference. A. 18 Pi feet B. 20 pi feet C. 35 pi feet D. 25 pi ... |
|