Find the quotients without actual divisions.(i)(a3 - 8) = (a -2)(ii)(2

1.	Find the quotients without actual divisions.(i)(a3 - 8) = (a -2)(ii)(27+3+8) = (3t+2)(iii)(8a3+27) + (4a2-6a+9)(iv) (64a3-125) + (16a2+20a+25).
Answer» 1)a^3-8/(a-2)=(a)^3 -(2)^3/(a-2)=(a-2)(a^2+2a+4)/(a-2)=a^2+2a+42)27t^3+8/(3t+2)(3t)^3+(2)^3/(3t+2)(3t+2)(9t^2-6t+4)/(3t+2)9t^2-6t+4 1) a^2+4+2a2)9t^2+4+6t3)2a+3 4)4a-5

Find the quotients without actual divisions.(i)(a3 - 8) = (a -2)(ii)(27+3+8) = (3t+2)(iii)(8a3+27) + (4a2-6a+9)(iv) (64a3-125) + (16a2+20a+25).

Answer»

1)a^3-8/(a-2)=(a)^3 -(2)^3/(a-2)=(a-2)(a^2+2a+4)/(a-2)=a^2+2a+42)27t^3+8/(3t+2)(3t)^3+(2)^3/(3t+2)(3t+2)(9t^2-6t+4)/(3t+2)9t^2-6t+4

1) a^2+4+2a2)9t^2+4+6t3)2a+3

4)4a-5