1.

Find the product:9t2(t + 7t3)

Answer»

9t2(t + 7t3)

Let p, q and r be three monomials.

Then, by distributive law of multiplication over addition, we have:

P × (q + r) = (p × q) + (p × r)

Now,

= (9t2 × t) + (9t2 × 7t3)

= (9t3 + 63t5) … [∵ am × an = am+n]



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