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Find the product:9t2(t + 7t3) |
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Answer» 9t2(t + 7t3) Let p, q and r be three monomials. Then, by distributive law of multiplication over addition, we have: P × (q + r) = (p × q) + (p × r) Now, = (9t2 × t) + (9t2 × 7t3) = (9t3 + 63t5) … [∵ am × an = am+n] |
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