1.

Find the product:(3/5)m2n(m + 5n)

Answer»

(3/5)m2n(m + 5n)

Let p, q and r be three monomials.

Then, by distributive law of multiplication over addition, we have:

P × (q + r) = (p × q) + (p × r)

Now,

= ((3/5)m2n × m) + ((3/5)m2n × 5n)

= ((3/5)m3n + 3m2n2) … [∵ am × an = am+n]



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