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Find the product:((2/5)x – (1/2)y) (10x – 8y) |
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Answer» ((2/5)x – (1/2)y) (10x – 8y) Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d) = ac – ad – bc + bd Let, a= (2/5)x, b=(1/2)y, c= 10x, d= 8y Now, = (2/5)x × (10x – 8y) – (1/2)y × (10x – 8y) = [((2/5)x × 10x) + ((2/5)x × -8y)] – [((1/2)y × 10x) + ((1/2)y × -8y)] = [4x2 – (16/5)xy – 5yx + 4y2] = [4x2 – (41/5)xy + 4y2] |
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