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Find the product:((1/5)x + 2y) ((2/3)x – y) |
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Answer» ((1/5)x + 2y) ((2/3)x – y) Suppose (a + b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a + b) × (c – d) = a × (c – d) + b × (c – d) = (a × c – a × d) + (b × c – b × d) = ac – ad + bc – bd Let, a= (1/5)x, b= 2y, c= (2/3)x, d= y Now, = (1/5)x × ((2/3)x – y) + 2y × ((2/3)x – y) = [((1/5)x × (2/3)x) + ((1/5)x × -y)] + [(2y × (2/3)x) + (2y × -y)] = [(2/15)x2 – (1/5)xy + (4/3)yx – 2y2)] = [(2/15)x2 + (17/15) xy – 2y2] |
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