Find the probility of choosing a prime number from the series of natur

1.	Find the probility of choosing a prime number from the series of natural number 170
Answer» Answer: THEORY : A sum of TWO perfect cubes, a3 + b3 can be factored into : \sf\green{ Mass \: of \: the \: OBJECT, \:}Massoftheobject, ━━━━━━━━━━━━━━━━━━━━━━━━━ ━━━━━━━━━━━━━━━━━━━━━━━━━ Proof : (a+b) • (a2-ab+b2) = a3-a2b+ab2+ba2-b2a+b3 = a3+(a2b-ba2)+(ab2-b2a)+b3= a3+0+0+b3= \sf\color{blue}{→a3+b3}→a3+b3 ━━━━━━━━━━━━━━━━━━━━━━━━━ ━━━━━━━━━━━━━━━━━━━━━━━━━ Check : 27 is the cube of 3 Check : r3 is the cube of r1 Check : P3 is the cube of p1 ━━━━━━━━━━━━━━━━━━━━━━━━━ ━━━━━━━━━━━━━━━━━━━━━━━━━ Factorization is : \mathrm{\boxed{\boxed{\PINK{→ (r + 3p) • (r2 - 3rp + 9p2) ✔}}}}→(r+3p)•(r2−3rp+9p2)✔

Find the probility of choosing a prime number from the series of natural number 170

Answer»

Answer:

THEORY :

A sum of TWO perfect cubes, a3 + b3 can be factored into :

\sf\green{ Mass \: of \: the \: OBJECT, \:}Massoftheobject,

━━━━━━━━━━━━━━━━━━━━━━━━━

Proof :

(a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

\sf\color{blue}{→a3+b3}→a3+b3

━━━━━━━━━━━━━━━━━━━━━━━━━

Check :

27 is the cube of 3

Check :

r3 is the cube of r1

Check :

P3 is the cube of p1

━━━━━━━━━━━━━━━━━━━━━━━━━

Factorization is :

\mathrm{\boxed{\boxed{\PINK{→ (r + 3p) • (r2 - 3rp + 9p2) ✔}}}}→(r+3p)•(r2−3rp+9p2)✔