1.

Find the probability that a non-leap year selected at random will have 53 Fridays.

Answer»

Any non-leap year has 365 days which is divided into 7x52=364 + 1 days.

There will be 52 fridays, one for each week except when the first day of the year is a Friday.

That probability is 1/7. Also, the probability of non-leap year is 3/4 so overall probability is 1/7*3/4=3/28



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