1.

Find the probability that a non – leap year contains (i) 53 Sundays (ii) 52 Sundays only.

Answer»

A non - leap year contains 365 days 52 weeks and 1 day more.

(i) We get 53 sundays when the remaining day is Sunday.

Number of days in the week = 7

∴ n(S) = 7

Number of ways getting 53 Sundays. n(E) = 1

∴ P(E) = n(E)/n(S) = 1/7

∴ Probability of getting 53 Sundays = 1/7

(ii) Probability of getting 52 Sundays P(vector E) = 1 – P(E)

= 1 – 1/7 = 6/7.



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