Saved Bookmarks
| 1. |
Find the probability that a non – leap year contains (i) 53 Sundays (ii) 52 Sundays only. |
|
Answer» A non - leap year contains 365 days 52 weeks and 1 day more. (i) We get 53 sundays when the remaining day is Sunday. Number of days in the week = 7 ∴ n(S) = 7 Number of ways getting 53 Sundays. n(E) = 1 ∴ P(E) = n(E)/n(S) = 1/7 ∴ Probability of getting 53 Sundays = 1/7 (ii) Probability of getting 52 Sundays P(vector E) = 1 – P(E) = 1 – 1/7 = 6/7. |
|