Find the probability of getting only 52 sundays in a non leap year

1.	Find the probability of getting only 52 sundays in a non leap year
Answer» There are 52 weeks in a way which means there will be 52 Sundays in a year. There are 365 days in a year but we have 366 days in a leap year. There are 7 days in a week. If we multiply the weeks by the days we have 52x7 which equals to 364. This means that there are 2 extra days in a leap year which will make it 366. The probability of having 52 Sundays in a leap year is thus: the remaining two days can be any of this formation: Sunday-Monday, Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday, Thursday-Friday, Friday-Saturday, Saturday-Sunday. However, to get 52 Sundays in a leap year, none of the remaining two days must be a Sunday. Therefore, out of the 7 combinations above, that can be only realized 5 out of 7 times. The connection "Sunday-Monday and Saturday-Sunday" most be scraped off. The probability of having 52 Sundays in a leap year is therefore 5/7.

Answer»

There are 52 weeks in a way which means there will be 52 Sundays in a year.

There are 365 days in a year but we have 366 days in a leap year.

There are 7 days in a week.

If we multiply the weeks by the days we have 52x7 which equals to 364. This means that there are 2 extra days in a leap year which will make it 366.

The probability of having 52 Sundays in a leap year is thus: the remaining two days can be any of this formation:

Sunday-Monday, Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday, Thursday-Friday, Friday-Saturday, Saturday-Sunday.

However, to get 52 Sundays in a leap year, none of the remaining two days must be a Sunday.

Therefore, out of the 7 combinations above, that can be only realized 5 out of 7 times. The connection "Sunday-Monday and Saturday-Sunday" most be scraped off.

The probability of having 52 Sundays in a leap year is therefore 5/7.

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