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Find the principal value of: `sin^(-1)(-1/2)`A. `-pi/6`B. `(5pi)/6`C. `(7pi)/6`D. none of these |
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Answer» Correct Answer - A Let `sin^(-1)(-1/2)=x`, where `x in [-pi/2,pi/2]`. Then, `sinx=-1/2=-sinpi/6=sin(-pi/6) rArr x=-pi/6`. |
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