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Find the principal value of each of the following :\(\cos^{-1}\left(\cos\frac{13\pi}{6}\right)\) |
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Answer» \(\cos^{-1}\left(\cos\frac{13\pi}{6}\right)\)\(=\cos^{-1}\left(\cos\left(2\pi+\frac{\pi}{6}\right)\right)\) [ Formula: cos (2π + x) = cos x , cos is positive in the first quadrant. ] \(\cos^{-1}\left(\cos\frac{\pi}{6}\right)\) [Formula: cos -1(cos x) = x] \(=\frac{\pi}{6}\) |
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