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Find the principal value of each of the following:\(tan^{-1}(\frac{1}{\sqrt3})\) |
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Answer» We know that, for any x ∈ R, tan-1represent an angle in \((\frac{-\pi}2,\frac{\pi}2)\) whose tangent is x. So, \(tan^{-1}(\frac{1}{\sqrt3})\) = An angle in \((\frac{-\pi}2,\frac{\pi}2)\) whose tangent is \(\frac{1}{\sqrt3}\) \(=-\frac{\pi}6\) \(\therefore\,tan^{-1}(\frac{1}{\sqrt3})=-\frac{\pi}6\) Hence, Principal value of tan-1\((\frac{1}{\sqrt3})\) is \(-\frac{\pi}6\). |
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