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Find the principal value of each of the following :\(\sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\) |
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Answer» \(\sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)\(=\pi-\sec^{-1}\left(\frac{2}{\sqrt{3}}\right)\) [ Formula: sec -1(-x)= π – sec -1(x) ] \(=\pi-\frac{\pi}{6}=\frac{5\pi}{6}\) |
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