Saved Bookmarks
| 1. |
Find the principal value of cot-1(- 1/√3) |
|
Answer» cot-1(- 1/√3) = π - cot-1(- 1/√3) [∵ cot-1(-x) = π – cot-1(x)] = π - π/3 ∴ cot-1(- 1/√3) = 2π/3 |
|