1.

Find the position of the object which when placed in front of a concave mirror ofradius of curvature 40 cm produces a virtual image, which is twice the size of theobject.

Answer»

Answer:

Explanation:

GIVEN:

focal length

f= -40cm

and magnification

m = +2 = -v/u

or

v= -2u_______(1)

now, the mirror relation is

1/f = 1/v + 1/u

or

-1/40 = (u + v)/uv

= u-2u /(-2u)2 [substituting value of v from EQ. (1)]

THUS, image DISTANCE will be

u= -20cm

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