1.

Find the polar co-ordinates of points whose Cartesian co-ordinates are: (-1, -1) 

Answer»

(x, y) = (-1, -1) 

∴ r = \(\sqrt {x^2+y^2} = \sqrt{1+1}=\sqrt2\)

tan θ = \(\frac{y}{x} = \frac {-1}{-1}=1\)

∴ tan θ = tan π/4

Since the given point lies in the 3rd quadrant, 

tan θ = tan (π + π/4) …[∵ tan (n + x) = tan x] 

∴ tan θ = tan (5π/4)

∴ θ = (5π/4) = 225° 

∴ the required polar co-ordinates are ( \(\sqrt2\), 225°).



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