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Find the polar co-ordinates of points whose Cartesian co-ordinates are: (-1, -1) |
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Answer» (x, y) = (-1, -1) ∴ r = \(\sqrt {x^2+y^2} = \sqrt{1+1}=\sqrt2\) tan θ = \(\frac{y}{x} = \frac {-1}{-1}=1\) ∴ tan θ = tan π/4 Since the given point lies in the 3rd quadrant, tan θ = tan (π + π/4) …[∵ tan (n + x) = tan x] ∴ tan θ = tan (5π/4) ∴ θ = (5π/4) = 225° ∴ the required polar co-ordinates are ( \(\sqrt2\), 225°). |
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