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Find the points on the x-axiswhow distance from the line(1/3 + y/4)=24/4=1 are 4 units |
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Answer» 3 x
+ 4 y
=1 or 4x+3y−12=0 Let (a,0) be the point on the x-axis whose DISTANCE from the given line is 4 units. Thus, using distance formula, 4= 4 2 +3 2
∣4a+3⋅0−12∣
⇒4= 5 ∣4a−12∣
⇒∣4a−12∣=20 ⇒±(4a−12)=20 ⇒(4a−12)=20or−(4a−12)=20 ⇒4a=20+12or4a=−20+12 ⇒a=8or−2 Thus, the required points on the x-axis are (−2,0) and (8,0) |
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