Find the points of trisection of line joining (2,6) and (4,8)

1.	Find the points of trisection of line joining (2,6) and (4,8)
Answer» ong>GIVEN Points →A(2,6) and B(4,8) →Trisect 2:1 , m = 2 and n = 1 We have →x₁ =2 , y₁ = 6 , x₂=4 and y₂ = 8 FORMULA $\to\sf \bigg(\dfrac{mx_2+nx_1}{m+n} \bigg),\bigg(\dfrac{my_2+ny_1}{m+n} \bigg)$ Put The Value on formula $\to\sf\bigg(\dfrac{2\times4+1\times2}{2+1} \bigg),\bigg(\dfrac{2\times8+1\times6}{2+1}\bigg)$ $\to\sf\bigg(\dfrac{8+2}{3} \bigg),\bigg(\dfrac{16+6}{3}\bigg)$ $\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)$ Answer $\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)$

Answer»

ong>GIVEN Points

→A(2,6) and B(4,8)

→Trisect 2:1 , m = 2 and n = 1

We have

→x₁ =2 , y₁ = 6 , x₂=4 and y₂ = 8

$\to\sf \bigg(\dfrac{mx_2+nx_1}{m+n} \bigg),\bigg(\dfrac{my_2+ny_1}{m+n} \bigg)$