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| 1. |
Find the point on x-axis which is equidistant from the points (2,-2) and (-4,2) |
| Answer» Let the point A(2,-2), B(-4,2) and (x,0) is equidistant from point P and Q.Now, using distance formula to find PA and AQ in both conditions PA=PB PA²=PB² (x-2)²+(0+2)² =(x+4)²+(0-2)² X²+4-4x+4=x²+16+8x+4 -4x+4=8x+16 X=-1Now, P(-1,0) | |