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Find the point on x axis which is equidistant from the point (2 - 2 )and (-4 2) |
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Answer» ong>Answer: POINT p is equidistant from a and b coordinates of a =(2,-2) coordinates of b = (-4,2) coordinates of p = (X,0) pa = pb sw.root (x-2)2+(0+2)2 = sq.root(x+4)2+(0-2)2 (x-2)2+4 = (x+4)2+4 x2+4-4x = x2+16+8x 4-4x = 16+8x -12 = 12 x x = -1 |
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