1.

Find the point on x axis which is equidistant from the point (2 - 2 )and (-4 2)​

Answer»

ong>Answer:

POINT p is equidistant from a and b

coordinates of a =(2,-2)

coordinates of b = (-4,2)

coordinates of p = (X,0)

pa = pb

sw.root (x-2)2+(0+2)2 = sq.root(x+4)2+(0-2)2

(x-2)2+4 = (x+4)2+4

x2+4-4x = x2+16+8x

4-4x = 16+8x

-12 = 12 x

x = -1



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