1.

Find the point on the y-axis which is equidistant from points 5, -2,and 3,-2

Answer»

<P>Step-by-step explanation:

LET P(0,y) be any point on y-axis.

Let A(5,−2) and B(−3,2). Then,

PA=PB

PA2=PB2

(5−0)2+(−2−y)2=(−3−0)2+(2−y)2

25+4+y2+4y=9+4+y2−4y

8y=−16

y=−2

Therefore, the required point is (0,−2)



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