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Find the point on the y-axis which is equidistant from points 5, -2,and 3,-2 |
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Answer» <P>Step-by-step explanation: LET P(0,y) be any point on y-axis. Let A(5,−2) and B(−3,2). Then, PA=PB PA2=PB2 (5−0)2+(−2−y)2=(−3−0)2+(2−y)2 25+4+y2+4y=9+4+y2−4y 8y=−16 y=−2 Therefore, the required point is (0,−2) |
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