1.

Find the point on the curve `y^2=4x`which is nearest to the point (2, 1).

Answer» `B(x_o,y_o)`
normal at B passes through A
`(y-y_o)=-1/(dy/dx)*(x-x_o)`
`(y-y_o)=-y_o/2(x-x_o)``1-y_o=-y_o +(x_oy_o)/2`
`x_oy_o=2`
`y_o^2=4x_o`
`x_oy_o*y_o^2=2*4x_o`
`y_o^3=8`
`y_o=2`
`x_o=1`
point(1,2).


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