Find the point of the X-axis which is equidistant from (2, -5) and (-2

1.	Find the point of the X-axis which is equidistant from (2, -5) and (-2,9)
Answer» The point equidistant will be the MIDPOINT $x = \frac{x1 + x2}{2} \\ y = \frac{y1 + 2}{2} \\ \\ x = \frac{2 - 2}{2} \\ x = 0 \\ \\ y = \frac{ - 5 + 9}{2 } \\ y = 2$ Therefore the POINTS (0,2) will be equidistant. *HOPE* *THIS* *HELPS* *PLZ* *MARK* AS *BRAINLIEST*.

Find the point of the X-axis which is equidistant from (2, -5) and (-2,9)

Answer»

The point equidistant will be the MIDPOINT

$x = \frac{x1 + x2}{2} \\ y = \frac{y1 + 2}{2} \\ \\ x = \frac{2 - 2}{2} \\ x = 0 \\ \\ y = \frac{ - 5 + 9}{2 } \\ y = 2$

Therefore the POINTS (0,2) will be equidistant.

HOPE THIS HELPS PLZ MARK AS BRAINLIEST.

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Find the point of the X-axis which is equidistant from (2, -5) and (-2,9)​

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Find the point of the X-axis which is equidistant from (2, -5) and (-2,9)