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Find the ph of a solution obtained by mixing 10ml of 0.45m hcl and 40ml of 0.1m naoh? |
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Answer» arity of HCl be M1 and vol be V1 M1v1 = 0.1×40 = 4 LET molarity of NaOH be M2 and vol be V2 M2v2 = 0.45×10= 4.5 Clearly m2v2 >m1v1 THEREFORE resulting SOLUTION will be basic. So molarity if resultant solution ll be M = m2v2 - m1v1/ v1 + v2 = 0.01 POH = -log(0.01) = 2 Therefore, pH = 14 - pOH = 12. |
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