Saved Bookmarks
| 1. |
Find the perimeters of (i) AABE (ii) the rectangle BCDE inthis figure. Which figure has greater perimetre and by howmuch? |
|
Answer» Perimeter of ΔABE = AB+BE+AE = 3 3
+2 5 1
+4 3 2
= 3 10
+ 5 11
+ 3 14
= 15 50+33+70
= 15 153
=10 15 3
cm Perimeter of Rectangle BCDE = 2(l+b) =2(2 5 1
+1 3 2
) =2( 5 11
+ 3 5
) =2( 15 33+25
) =2( 15 58
) = 15 116
=7 15 11
cm So,ΔABE has greater perimeter Difference of perimeter = 15 153
− 15 116
= 15 37
=2 15 7
cm Hence ΔABE has greater perimeter by =2 15 7
cm |
|