Find the perimeter of the rectangle whose length is 40cm and a diagona

1.	Find the perimeter of the rectangle whose length is 40cm and a diagonal is 41cm.Explain it too.
Answer» Step-by-step EXPLANATION: LENGTH = 40 cm(GIVEN) Diagonal = 41 cm Diagonal = $\sqrt{(length)^{2}+(breadth)^{2} }$ 41= $\sqrt{(40)^{2}+b^{2} }$ $1600+b^{2} =41^{2}$ $1600+b^{2} =1681$ $b^{2} =1681-1600$ $b^{2} =81$ $b=\sqrt{81}$ $b=\sqrt{99}$ ∴b=9 cm Perimeter of a rectangle = 2(l+b) = 2(40+9) = 249 = 98 cm Hence, the perimeter of the rectangle is 98 cm. Hope this helps you. Please mark me as a Brainliest if this helped...