Find the perimeter of an isosceles triangle right angle triangle havin

1.	Find the perimeter of an isosceles triangle right angle triangle having area 200 CM square
Answer» $\huge\underline\mathfrak{Answer:}$ LET each equal SIDE be x of an isosceles right triangle ABC. Then AREA of an ISOSCELES right triangle ABC $\sf\frac{1}{2}$ (x $\times$ x)= $\sf\frac{1}{2}x^2$ But area of a triangle = $\sf{200\:cm^2}$ •°• $\sf\frac{1}{2}x^2=200$ $\implies$ $\sf{x^2=400=20\times}$ $\implies$ $\sf{x=20cm}$ •°• Hypotenuse AC of ∆ABC = $\sf\sqrt{x^2+x^2}$ cm = $\sf\sqrt{2x^2}$ cm = $\sqrt{2}$ x cm. Now, the perimeter of an isosceles right triangle = $\sf{(x+x+}$ $\sf\sqrt{2x)}$ cm = $\sf{(20+20+20}$ $\sf\sqrt{2)}$ cm = $\sf{(40+20}$ $\sf\sqrt{2}$ cm 20√2 (√2 + 1) cm.