1.

Find the percentage increaseand in the area of a triangleat its each side is doubled​

Answer»

The area before :

area1=
\frac{1}{2} \times <klux>H</klux> \times <klux>B</klux>
Where h = HEIGHT and b = base.

The area after increasing the sides,

area2=
\frac{1}{2} (2h)(2b) \\ = 4( \frac{1}{2} \times h \times b)

So the increase in area in % will be,

\frac{4( area_{1} )- (area_{1}) }{ area_{2} } \times 100 \\ \frac{3area_{1}}{area_{2}} \times 100 \\ \frac{3}{4} \times 100 \\ = 75\%


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