Find the percentage composition of each element in Glucose (C6 H12 O6)

1.	Find the percentage composition of each element in Glucose (C6 H12 O6).
Answer» Answer: %Composition of Carbon = 40%, of oxygen = 53.33% , of HYDROGEN = 6.67% EXPLANATION: To find the percentage composition of each element, we need the masses of each individual element and the mass of glucose itself. Mass of carbon = 12g Mass of Hydrogen = 1g Mass of Oxygen = 16g Mass of glucose, is therefore = 126 + 112 + 166 (6 carbons 12g + 12 hydrogens * 1g + 6 oxygens * 16g) = 180g Now, to find percentage composition, we use this formula Percentage composition = (Total weight of element / Weight of compound)100. For carbon, %composition = (72/180)100 = 40% (72 because 126) For hydrogen %composition = (12/180)100 = 6.67% (12 because 112) For oxygen %composition = (96/180)100 = 53.33% (96 because 16*6) Adding them up, we see 40+6.67+53.33 = 100.

Find the percentage composition of each element in Glucose (C6 H12 O6).

Answer»

Answer:

%Composition of Carbon = 40%, of oxygen = 53.33% , of HYDROGEN = 6.67%

To find the percentage composition of each element, we need the masses of each individual element and the mass of glucose itself.

Mass of carbon = 12g

Mass of Hydrogen = 1g

Mass of Oxygen = 16g

Mass of glucose, is therefore = 12*6 + 1*12 + 16*6 (6 carbons * 12g + 12 hydrogens * 1g + 6 oxygens * 16g) = 180g

Now, to find percentage composition, we use this formula

Percentage composition = (Total weight of element / Weight of compound)*100.

For carbon,

%composition = (72/180)*100 = 40% (72 because 12*6)

For hydrogen

%composition = (12/180)*100 = 6.67% (12 because 1*12)

For oxygen

%composition = (96/180)*100 = 53.33% (96 because 16*6)

Adding them up, we see 40+6.67+53.33 = 100.