find the number of sides of a regular polygon whose each exterior angl

1.	find the number of sides of a regular polygon whose each exterior angle has a measure of 45°.
Answer» $\huge{\underline{\mathtt{\red{q}\pink{u}\green{e}\blue{s}\purple{t}\orange{i}\blue{o}\purple{n}}}}$ FIND the NUMBER of sides of a REGULAR polygon whose each exterior angle has a MEASURE of 45°. $\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$ total measure of all exterior ANGLES=360° measure of each exterior angle=45° therefore,the number of exterior angles = 360/45=8 the polygon has 8 sides.

find the number of sides of a regular polygon whose each exterior angle has a measure of 45°.

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$\huge{\underline{\mathtt{\red{q}\pink{u}\green{e}\blue{s}\purple{t}\orange{i}\blue{o}\purple{n}}}}$

FIND the NUMBER of sides of a REGULAR polygon whose each exterior angle has a MEASURE of 45°.

$\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

total measure of all exterior ANGLES=360°

measure of each exterior angle=45°

therefore,the number of exterior angles = 360/45=8

the polygon has 8 sides.

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find the number of sides of a regular polygon whose each exterior angle has a measure of 45°.​

FIND the NUMBER of sides of a REGULAR polygon whose each exterior angle has a MEASURE of 45°.

total measure of all exterior ANGLES=360°

measure of each exterior angle=45°

therefore,the number of exterior angles = 360/45=8

the polygon has 8 sides.

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find the number of sides of a regular polygon whose each exterior angle has a measure of 45°.