1.

Find the number of lead balls, each 1 cm in diameter that can be a sphere of diameter 12 cm.

Answer»

Volume of larger sphere = (4/3)π*6*6*6) cm3 = 288π cm3

Volume of 1 small lead ball = ((4/3)π*(1/2)*(1/2)*(1/2)) cm3 = π/6 cm3 . 

Number of lead balls = (288π*(6/π)) = 1728.



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