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Find the number of distinct normals that can be drawn from `(-2,1)`to the parabola `y^2-4x-2y-3=0`A. 1B. 2C. 3D. 0 |
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Answer» Correct Answer - A The equation of the parabola is `(y-1)^(2)=4(x+1)`. The equation of any normal to this parabola is `y-1=m(x+1)-2m-m^(3)` If passes through (-2, 1). Then, `0=-m-2m-m^(3)rArrm^(3)+3m=0rArrm=0" "[becausem^(2)+3ne0]` So, there is only one normal passing through (-2, 1). |
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