Find the number of atoms present in 3.42 grams of cane sugar

1.	Find the number of atoms present in 3.42 grams of cane sugar
Answer» Answer: 6.022×10^22 molecules Explanation: MOLECULAR mass of CANE sugar (C6H22O11) = 342g 1 mole of C6H22O11 = 342g 342 g of cane sugar CONTAIN 6.022 X 1023 molecules 34.2 g of cane sugar will contain = 6.022 x 1022 molecules

Answer»

Answer:

6.022×10^22 molecules

Explanation:

MOLECULAR mass of CANE sugar (C6H22O11) = 342g

1 mole of C6H22O11 = 342g

342 g of cane sugar CONTAIN 6.022 X 1023 molecules

34.2 g of cane sugar will contain = 6.022 x 1022 molecules

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