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Find the normal equation of regression for y=a+bx+cx2+dx3 |
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Answer» HEY user !! Step-by-step explanation: The formula for REGRESSION Analysis – Y = a + bX + ∈ Y = Stands for the dependent variable X = Stands for an independent variable a = Stands for the intercept b = Stands for the slope ∈ = Stands for the error term The formula for intercept “a” and the slope “b” can be calculated as per below. a = (Σy)(Σx2) – (Σx)(Σxy)/ n(Σx2) – (Σx)2 b = n (Σxy) – (Σx)(Σy) /n(Σx2) – (Σx)2 Y = a + bX1 + cX2 + dX3 + ∈ Where, Y – Dependent variable X1, X2, X3 – Independent (explanatory) variables a – Intercept b, c, d – Slopes ϵ – Residual (error) a = (((Σy) * (Σx2)) – ((Σx) * (Σxy))) / n * (Σx2) – (Σx)2 a = ((25 * 120) – (20 * 144)) / (4*120 – (20)2) a = 1.5 b (Slope) is calculated using the formula given below b = ((n * (Σxy)) – ((Σx) * (Σy))) / (n * (Σx2)) – (Σx)2 b = ((4 * 144) – (20 * 25)) / (4*120 – (20)2) b = 0.95 So the regression line can be defined as Y = a +bX which is Y = 1.5 + 0.95 * |
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